Mathematics · Frontier · 30 min · Chapter 18 of 28
Topology
What remains of geometry when you may bend and stretch but not tear: open sets, continuity, compactness, and connectedness.
Read first: Real analysis, The language of proof
The idea
Topology keeps continuity and throws away distance, or rather, it notices that continuity can be stated without numbers. You declare which sets are open. The declaration must include the empty set and the whole space, and it must survive arbitrary unions and finite intersections. In the real line the open sets are unions of open intervals, and that choice reproduces the ε–δ notion of continuity. Other choices of open sets give other geometries: the discrete topology makes every function continuous, the indiscrete topology makes only constants continuous into a Hausdorff space.
With open sets in hand, continuity is a single sentence: f is continuous when f⁻¹(U) is open whenever U is open. Sequences are no longer the definition, though in metric spaces they still detect the same closed sets. A homeomorphism is a continuous bijection with continuous inverse. It is the notion of “the same shape” for a topologist. A coffee cup with a handle and a doughnut are homeomorphic; a coffee cup and a ball are not, because removing a circle can disconnect one and not the other in a way no homeomorphism can repair. That invariant is the start of algebraic topology.
Two properties do most of the work that closed intervals did in analysis. A space is compact when every cover by open sets has a finite subcover. A continuous image of a compact space is compact, so a continuous real function on a compact set attains its bounds — the extreme value theorem, with the interval hypothesis replaced by the property that made the proof work. A space is connected when it is not the union of two nonempty disjoint open sets. Continuous images of connected sets are connected, which is the intermediate value theorem in its natural habitat.
Hold onto this
- A topology is a family of open sets closed under arbitrary unions and finite intersections.
- A function is continuous exactly when the preimage of every open set is open.
- Compact sets are those for which every open cover has a finite subcover. In Rⁿ they are the closed bounded sets.
- Connected means the set is not the union of two nonempty disjoint open pieces.
Formulas
Continuity
The definition of a continuous map between topological spaces.
- f⁻¹(U)
- The set of points sent into U, not an inverse function
Compactness
Every open cover has a finite subcover. In Rⁿ, equivalent to closed and bounded.
- Uα
- Open sets whose union is the whole space
Connectedness
The space cannot be split into two nonempty disjoint open pieces.
- A, B
- Open subsets of X
Homeomorphism
A reversible continuous deformation. The two spaces are topologically the same.
- f⁻¹
- The inverse function, which must also be continuous
Worked examples
1. Open, closed, neither
In the real line with the standard topology, classify (0, 1), [0, 1], and (0, 1].
- (0, 1) is a basic open interval, hence open. It is not closed: its complement is not open, since 0 is a boundary point.
- [0, 1] is closed and bounded, hence compact. It is not open.
- (0, 1] is neither. Any neighborhood of 1 leaves the set, so it is not open; 0 is a missing limit point, so it is not closed.
Open; closed (and compact); neither.
2. Why 1/x has no maximum on (0, 1]
f(x) = 1/x on (0, 1] is continuous. Why does the extreme value theorem not apply?
- The theorem needs a compact domain.
- (0, 1] is not closed, hence not compact in R.
- Indeed f is unbounded: as x approaches 0, f exceeds every candidate maximum.
The hypothesis fails, and so does the conclusion. On [δ, 1] for any δ > 0 the maximum exists and equals 1/δ.
Try these
The map t ↦ (cos 2πt, sin 2πt) sends [0, 1) continuously onto the unit circle, and it is one-to-one. Is it a homeomorphism?
Are the rationals connected in the subspace topology?
Common mistakes
- “Open” is relative to the space you are in. (0, 1] is not open in R, but it is open in the space (0, 1].
- A continuous bijection need not have a continuous inverse. Compactness of the domain plus a Hausdorff codomain repairs this.
- Closed and bounded is compactness only in Rⁿ with the standard metric. In infinite-dimensional spaces it fails.